0.5b+4=1/3(6b+12)

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Solution for 0.5b+4=1/3(6b+12) equation: 



0.5b+4=1/3(6b+12)

We move all terms to the left:

0.5b+4-(1/3(6b+12))=0



Domain of the equation: 3(6b+12))!=0

b∈R



We multiply all the terms by the denominator


(0.5b)*3(6b+12))-(1+4*3(6b+12))=0

We add all the numbers together, and all the variables

(+0.5b)*3(6b+12))-(1+4*3(6b+12))=0

Wy multiply elements

(+0.5b)*3(6b+12))-(1+12b(6=0

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