0.5n(n+1)=28

Solution for 0.5n(n+1)=28 equation:

0.5n(n+1)=28

We move all terms to the left:

0.5n(n+1)-(28)=0

We multiply parentheses

0n^2+0n-28=0

We add all the numbers together, and all the variables

n^2+n-28=0

a = 1; b = 1; c = -28;
Δ = b2-4ac
Δ = 12-4·1·(-28)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{113}}{2*1}=\frac{-1-\sqrt{113}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{113}}{2*1}=\frac{-1+\sqrt{113}}{2}
$