0.5n(n+1)=55

Solution for 0.5n(n+1)=55 equation:

0.5n(n+1)=55

We move all terms to the left:

0.5n(n+1)-(55)=0

We multiply parentheses

0n^2+0n-55=0

We add all the numbers together, and all the variables

n^2+n-55=0

a = 1; b = 1; c = -55;
Δ = b2-4ac
Δ = 12-4·1·(-55)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{221}}{2*1}=\frac{-1-\sqrt{221}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{221}}{2*1}=\frac{-1+\sqrt{221}}{2}
$