0.5x(2x-4)=-17

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Solution for 0.5x(2x-4)=-17 equation: 



0.5x(2x-4)=-17

We move all terms to the left:

0.5x(2x-4)-(-17)=0

We add all the numbers together, and all the variables

0.5x(2x-4)+17=0

We multiply parentheses

0x^2+0x+17=0

We add all the numbers together, and all the variables

x^2+x+17=0

a = 1; b = 1; c = +17;
Δ = b2-4ac
Δ = 12-4·1·17
Δ = -67
Delta is less than zero, so there is no solution for the equation

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