0.5x(x-3)=(x-3)(1.x-1)

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Solution for 0.5x(x-3)=(x-3)(1.x-1) equation: 



0.5x(x-3)=(x-3)(1.x-1)

We move all terms to the left:

0.5x(x-3)-((x-3)(1.x-1))=0

We add all the numbers together, and all the variables

0.5x(x-3)-((x-3)(x-1))=0

We multiply parentheses

0x^2+0x-((x-3)(x-1))=0

We multiply parentheses ..

0x^2-((+x^2-1x-3x+3))+0x=0



We calculate terms in parentheses: -((+x^2-1x-3x+3)), so:

(+x^2-1x-3x+3)

We get rid of parentheses

x^2-1x-3x+3

We add all the numbers together, and all the variables

x^2-4x+3

Back to the equation:

-(x^2-4x+3)



We add all the numbers together, and all the variables

x^2+x-(x^2-4x+3)=0

We get rid of parentheses

x^2-x^2+x+4x-3=0

We add all the numbers together, and all the variables

5x-3=0

We move all terms containing x to the left, all other terms to the right

5x=3

x=3/5

x=3/5

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