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0.5x+(4/5)x=x+12
We move all terms to the left:
0.5x+(4/5)x-(x+12)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
0.5x+(+4/5)x-(x+12)=0
We multiply parentheses
4x^2+0.5x-(x+12)=0
We get rid of parentheses
4x^2+0.5x-x-12=0
We add all the numbers together, and all the variables
4x^2-0.5x-12=0
a = 4; b = -0.5; c = -12;
Δ = b2-4ac
Δ = -0.52-4·4·(-12)
Δ = 192.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{192.25}}{2*4}=\frac{0.5-\sqrt{192.25}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{192.25}}{2*4}=\frac{0.5+\sqrt{192.25}}{8} $
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