0.5x+1/2=25/50-(0.5x+3)

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Solution for 0.5x+1/2=25/50-(0.5x+3) equation: 



0.5x+1/2=25/50-(0.5x+3)

We move all terms to the left:

0.5x+1/2-(25/50-(0.5x+3))=0



Domain of the equation: 50-(0.5x+3))!=0

We move all terms containing x to the left, all other terms to the right

-(0.5x+3))!=-50

x∈R



We calculate fractions


0.5x+()/(-(0.5x+3))*2-(0.5x+3))+1*50)/(-(0.5x+50)+(+3))*2+50)=0

We add all the numbers together, and all the variables

0.5x+()/(-(0.5x+3))*2-(0.5x+3))+1*50)/(-(0.5x+50)+3)*2+50)=0

We add all the numbers together, and all the variables

0.5x+()/(-(0.5x+3))*2-(0.5x+3))+1*50)/(-(0.5x=0

We calculate fractions


0.5x+(()*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x)+(-(0.5x+3))+1*50)*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x)=0



We calculate terms in parentheses: +(()*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x)+(-(0.5x+3))+1*50)*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x), so:

()*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x)+(-(0.5x+3))+1*50)*(-(0.5x)/((-(0.5x+3))*2*(-(0.5x

We can not solve this equation

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