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0.5x+1/3x+8=x
We move all terms to the left:
0.5x+1/3x+8-(x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-0.5x+1/3x+8=0
We multiply all the terms by the denominator
-(0.5x)*3x+8*3x+1=0
We add all the numbers together, and all the variables
-(+0.5x)*3x+8*3x+1=0
We multiply parentheses
-0x^2+8*3x+1=0
Wy multiply elements
-0x^2+24x+1=0
We add all the numbers together, and all the variables
-1x^2+24x+1=0
a = -1; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·(-1)·1
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{145}}{2*-1}=\frac{-24-2\sqrt{145}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{145}}{2*-1}=\frac{-24+2\sqrt{145}}{-2} $
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