0.5x+2=1/6x-1

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Solution for 0.5x+2=1/6x-1 equation:



0.5x+2=1/6x-1
We move all terms to the left:
0.5x+2-(1/6x-1)=0
Domain of the equation: 6x-1)!=0
x∈R
We get rid of parentheses
0.5x-1/6x+1+2=0
We multiply all the terms by the denominator
(0.5x)*6x+1*6x+2*6x-1=0
We add all the numbers together, and all the variables
(+0.5x)*6x+1*6x+2*6x-1=0
We multiply parentheses
0x^2+1*6x+2*6x-1=0
Wy multiply elements
0x^2+6x+12x-1=0
We add all the numbers together, and all the variables
x^2+18x-1=0
a = 1; b = 18; c = -1;
Δ = b2-4ac
Δ = 182-4·1·(-1)
Δ = 328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{328}=\sqrt{4*82}=\sqrt{4}*\sqrt{82}=2\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{82}}{2*1}=\frac{-18-2\sqrt{82}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{82}}{2*1}=\frac{-18+2\sqrt{82}}{2} $

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