0.5x+4/3x=x+0

Solution for 0.5x+4/3x=x+0 equation:

0.5x+4/3x=x+0

We move all terms to the left:

0.5x+4/3x-(x+0)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

0.5x+4/3x-(+x)=0

We get rid of parentheses

0.5x+4/3x-x=0

We multiply all the terms by the denominator


(0.5x)*3x-x*3x+4=0

We add all the numbers together, and all the variables

(+0.5x)*3x-x*3x+4=0

We multiply parentheses

0x^2-x*3x+4=0

Wy multiply elements

0x^2-3x^2+4=0

We add all the numbers together, and all the variables

-2x^2+4=0

a = -2; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-2)·4
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*-2}=\frac{0-4\sqrt{2}}{-4}
=-\frac{4\sqrt{2}}{-4}
=-\frac{\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*-2}=\frac{0+4\sqrt{2}}{-4}
=\frac{4\sqrt{2}}{-4}
=\frac{\sqrt{2}}{-1}
$