0.5x2+-7x+6=0

Solution for 0.5x2+-7x+6=0 equation:

0.5x^2+-7x+6=0

We add all the numbers together, and all the variables

0.5x^2-7x=0

a = 0.5; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·0.5·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*0.5}=\frac{0}{1}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*0.5}=\frac{14}{1}
=14
$