0.5x2+0.25,x=5

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Solution for 0.5x2+0.25,x=5 equation:



0.5x^2+0.25.x=5
We move all terms to the left:
0.5x^2+0.25.x-(5)=0
We add all the numbers together, and all the variables
0.5x^2-5=0
a = 0.5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·0.5·(-5)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*0.5}=\frac{0-\sqrt{10}}{1} =-\frac{\sqrt{}}{1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*0.5}=\frac{0+\sqrt{10}}{1} =\frac{\sqrt{}}{1} $

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