0.5y-0.1(y+3)=0.2(2y+1)-0.7

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Solution for 0.5y-0.1(y+3)=0.2(2y+1)-0.7 equation: 


Simplifying
0.5y + -0.1(y + 3) = 0.2(2y + 1) + -0.7

Reorder the terms:
0.5y + -0.1(3 + y) = 0.2(2y + 1) + -0.7
0.5y + (3 * -0.1 + y * -0.1) = 0.2(2y + 1) + -0.7
0.5y + (-0.3 + -0.1y) = 0.2(2y + 1) + -0.7

Reorder the terms:
-0.3 + 0.5y + -0.1y = 0.2(2y + 1) + -0.7

Combine like terms: 0.5y + -0.1y = 0.4y
-0.3 + 0.4y = 0.2(2y + 1) + -0.7

Reorder the terms:
-0.3 + 0.4y = 0.2(1 + 2y) + -0.7
-0.3 + 0.4y = (1 * 0.2 + 2y * 0.2) + -0.7
-0.3 + 0.4y = (0.2 + 0.4y) + -0.7

Reorder the terms:
-0.3 + 0.4y = 0.2 + -0.7 + 0.4y

Combine like terms: 0.2 + -0.7 = -0.5
-0.3 + 0.4y = -0.5 + 0.4y

Add '-0.4y' to each side of the equation.
-0.3 + 0.4y + -0.4y = -0.5 + 0.4y + -0.4y

Combine like terms: 0.4y + -0.4y = 0.0
-0.3 + 0.0 = -0.5 + 0.4y + -0.4y
-0.3 = -0.5 + 0.4y + -0.4y

Combine like terms: 0.4y + -0.4y = 0.0
-0.3 = -0.5 + 0.0
-0.3 = -0.5

Solving
-0.3 = -0.5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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