0.6(1x+2)=0.55(2x+3)

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Solution for 0.6(1x+2)=0.55(2x+3) equation: 



0.6(1x+2)=0.55(2x+3)

We move all terms to the left:

0.6(1x+2)-(0.55(2x+3))=0

We add all the numbers together, and all the variables

0.6(x+2)-(0.55(2x+3))=0

We multiply parentheses

0.6x-(0.55(2x+3))+1.2=0



We calculate terms in parentheses: -(0.55(2x+3)), so:

0.55(2x+3)

We multiply parentheses

1.1x+1.65

Back to the equation:

-(1.1x+1.65)



We get rid of parentheses

0.6x-1.1x-1.65+1.2=0

We add all the numbers together, and all the variables

-0.5x-0.45=0

We move all terms containing x to the left, all other terms to the right

-0.5x=0.45

x=0.45/-0.5

x=-0.45/0.5

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