0.6(4x)-0.6(0.3)=0.5(3x)+0.5(0.8)+0.05

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Solution for 0.6(4x)-0.6(0.3)=0.5(3x)+0.5(0.8)+0.05 equation: 



0.6(4x)-0.6(0.3)=0.5(3x)+0.5(0.8)+0.05

We move all terms to the left:

0.6(4x)-0.6(0.3)-(0.5(3x)+0.5(0.8)+0.05)=0

We add all the numbers together, and all the variables

0.64x-(0.53x+0.5(0.8)+0.05)-0.18=0



We calculate terms in parentheses: -(0.53x+0.5(0.8)+0.05), so:

0.53x+0.5(0.8)+0.05

determiningTheFunctionDomain
0.53x+0.05+0.5(0.8)

We add all the numbers together, and all the variables

0.53x+0.45

Back to the equation:

-(0.53x+0.45)



We get rid of parentheses

0.64x-0.53x-0.45-0.18=0

We add all the numbers together, and all the variables

0.11x-0.63=0

We move all terms containing x to the left, all other terms to the right

0.11x=0.63

x=0.63/0.11

x=5+0.08/0.11

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