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0.64=r2
We move all terms to the left:
0.64-(r2)=0
We add all the numbers together, and all the variables
-1r^2+0.64=0
a = -1; b = 0; c = +0.64;
Δ = b2-4ac
Δ = 02-4·(-1)·0.64
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2.56}}{2*-1}=\frac{0-\sqrt{2.56}}{-2} =-\frac{\sqrt{}}{-2} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2.56}}{2*-1}=\frac{0+\sqrt{2.56}}{-2} =\frac{\sqrt{}}{-2} $
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