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0.6x(3200-0.2x)=2500
We move all terms to the left:
0.6x(3200-0.2x)-(2500)=0
We add all the numbers together, and all the variables
0.6x(-0.2x+3200)-2500=0
We multiply parentheses
0x^2+0x-2500=0
We add all the numbers together, and all the variables
x^2+x-2500=0
a = 1; b = 1; c = -2500;
Δ = b2-4ac
Δ = 12-4·1·(-2500)
Δ = 10001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{10001}}{2*1}=\frac{-1-\sqrt{10001}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{10001}}{2*1}=\frac{-1+\sqrt{10001}}{2} $
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