0.7(4x+3)=1.1-(x+5)

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Solution for 0.7(4x+3)=1.1-(x+5) equation: 



0.7(4x+3)=1.1-(x+5)

We move all terms to the left:

0.7(4x+3)-(1.1-(x+5))=0

We multiply parentheses

2.8x-(1.1-(x+5))+2.1=0



We calculate terms in parentheses: -(1.1-(x+5)), so:

1.1-(x+5)

determiningTheFunctionDomain
-(x+5)+1.1

We get rid of parentheses

-x-5+1.1

We add all the numbers together, and all the variables

-1x-3.9

Back to the equation:

-(-1x-3.9)



We get rid of parentheses

2.8x+1x+3.9+2.1=0

We add all the numbers together, and all the variables

3.8x+6=0

We move all terms containing x to the left, all other terms to the right

3.8x=-6

x=-6/3.8

x=-1+2.2/3.8

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