0.7(x-5)+0.5=1-0.3(10-2x)-0.5

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Solution for 0.7(x-5)+0.5=1-0.3(10-2x)-0.5 equation: 



0.7(x-5)+0.5=1-0.3(10-2x)-0.5

We move all terms to the left:

0.7(x-5)+0.5-(1-0.3(10-2x)-0.5)=0

We add all the numbers together, and all the variables

0.7(x-5)-(1-0.3(-2x+10)-0.5)+0.5=0

We multiply parentheses

0.7x-(1-0.3(-2x+10)-0.5)-3.5+0.5=0



We calculate terms in parentheses: -(1-0.3(-2x+10)-0.5), so:

1-0.3(-2x+10)-0.5

determiningTheFunctionDomain
-0.3(-2x+10)+1-0.5

We add all the numbers together, and all the variables

-0.3(-2x+10)+0.5

We multiply parentheses

0.6x-3+0.5

We add all the numbers together, and all the variables

0.6x-2.5

Back to the equation:

-(0.6x-2.5)



We add all the numbers together, and all the variables

0.7x-(0.6x-2.5)-3=0

We get rid of parentheses

0.7x-0.6x+2.5-3=0

We add all the numbers together, and all the variables

0.1x-0.5=0

We move all terms containing x to the left, all other terms to the right

0.1x=0.5

x=0.5/0.1

x=5

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