0.72p2-1.75p+0.5=0

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Solution for 0.72p2-1.75p+0.5=0 equation:



0.72p^2-1.75p+0.5=0
a = 0.72; b = -1.75; c = +0.5;
Δ = b2-4ac
Δ = -1.752-4·0.72·0.5
Δ = 1.6225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.75)-\sqrt{1.6225}}{2*0.72}=\frac{1.75-\sqrt{1.6225}}{1.44} $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.75)+\sqrt{1.6225}}{2*0.72}=\frac{1.75+\sqrt{1.6225}}{1.44} $

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