0.75-i=(6/8-i)

Solution for 0.75-i=(6/8-i) equation:

0.75-i=(6/8-i)

We move all terms to the left:

0.75-i-((6/8-i))=0


Domain of the equation: 8-i))!=0

We move all terms containing i to the left, all other terms to the right

-i))!=-8

i!=-8/1

i!=-8

i∈R


We add all the numbers together, and all the variables

-i-((-1i+6/8))+0.75=0

We add all the numbers together, and all the variables

-1i-((-1i+6/8))+0.75=0

We multiply all the terms by the denominator


-1i*8))-((-1i+6+(0.75)*8))=0

We add all the numbers together, and all the variables

-1i-1i*8))-((=0

Wy multiply elements

-8i^2-1i=0

a = -8; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-8)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-8}=\frac{0}{-16}
=0
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-8}=\frac{2}{-16}
=-1/8
$