0.75=1.2x+0x(1-x)

Solution for 0.75=1.2x+0x(1-x) equation:

0.75=1.2x+0x(1-x)

We move all terms to the left:

0.75-(1.2x+0x(1-x))=0

We add all the numbers together, and all the variables

-(1.2x+0x(-1x+1))+0.75=0


We calculate terms in parentheses: -(1.2x+0x(-1x+1)), so:

1.2x+0x(-1x+1)

We multiply parentheses

0x^2+1.2x+0x

We add all the numbers together, and all the variables

x^2+2.2x

Back to the equation:

-(x^2+2.2x)


We get rid of parentheses

-x^2-2.2x+0.75=0

We add all the numbers together, and all the variables

-1x^2-2.2x+0.75=0

a = -1; b = -2.2; c = +0.75;
Δ = b2-4ac
Δ = -2.22-4·(-1)·0.75
Δ = 7.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.2)-\sqrt{7.84}}{2*-1}=\frac{2.2-\sqrt{7.84}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.2)+\sqrt{7.84}}{2*-1}=\frac{2.2+\sqrt{7.84}}{-2}
$