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0.75q^2=108
We move all terms to the left:
0.75q^2-(108)=0
a = 0.75; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·0.75·(-108)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*0.75}=\frac{-18}{1.5} =-12 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*0.75}=\frac{18}{1.5} =12 $
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