0.7y(y-14)-0.5y=32.2

Solution for 0.7y(y-14)-0.5y=32.2 equation:

0.7y(y-14)-0.5y=32.2

We move all terms to the left:

0.7y(y-14)-0.5y-(32.2)=0

We add all the numbers together, and all the variables

-0.5y+0.7y(y-14)-32.2=0

We multiply parentheses

0y^2-0.5y+0y-32.2=0

We add all the numbers together, and all the variables

y^2+0.5y-32.2=0

a = 1; b = 0.5; c = -32.2;
Δ = b2-4ac
Δ = 0.52-4·1·(-32.2)
Δ = 129.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{129.05}}{2*1}=\frac{-0.5-\sqrt{129.05}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{129.05}}{2*1}=\frac{-0.5+\sqrt{129.05}}{2}
$