0.8(10y-10)=2/7(7y+14)

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Solution for 0.8(10y-10)=2/7(7y+14) equation: 



0.8(10y-10)=2/7(7y+14)

We move all terms to the left:

0.8(10y-10)-(2/7(7y+14))=0



Domain of the equation: 7(7y+14))!=0

y∈R



We multiply parentheses

8y-(2/7(7y+14))-8=0

We multiply all the terms by the denominator


8y*7(7y+14))-(2-8*7(7y+14))=0

Wy multiply elements

56y^2(7-56y(7=0

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