0.8(x-2)+0.5=1-0.3(4-2x)-0.5

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Solution for 0.8(x-2)+0.5=1-0.3(4-2x)-0.5 equation: 



0.8(x-2)+0.5=1-0.3(4-2x)-0.5

We move all terms to the left:

0.8(x-2)+0.5-(1-0.3(4-2x)-0.5)=0

We add all the numbers together, and all the variables

0.8(x-2)-(1-0.3(-2x+4)-0.5)+0.5=0

We multiply parentheses

0.8x-(1-0.3(-2x+4)-0.5)-1.6+0.5=0



We calculate terms in parentheses: -(1-0.3(-2x+4)-0.5), so:

1-0.3(-2x+4)-0.5

determiningTheFunctionDomain
-0.3(-2x+4)+1-0.5

We add all the numbers together, and all the variables

-0.3(-2x+4)+0.5

We multiply parentheses

0.6x-1.2+0.5

We add all the numbers together, and all the variables

0.6x-0.7

Back to the equation:

-(0.6x-0.7)



We add all the numbers together, and all the variables

0.8x-(0.6x-0.7)-1.1=0

We get rid of parentheses

0.8x-0.6x+0.7-1.1=0

We add all the numbers together, and all the variables

0.2x-0.4=0

We move all terms containing x to the left, all other terms to the right

0.2x=0.4

x=0.4/0.2

x=2

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