0.9x-2.1+0.9=0,2(5-x)

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Solution for 0.9x-2.1+0.9=0,2(5-x) equation:



0.9x-2.1+0.9=0.2(5-x)
We move all terms to the left:
0.9x-2.1+0.9-(0.2(5-x))=0
We add all the numbers together, and all the variables
0.9x-(0.2(-1x+5))-2.1+0.9=0
We add all the numbers together, and all the variables
0.9x-(0.2(-1x+5))-1.2=0
We calculate terms in parentheses: -(0.2(-1x+5)), so:
0.2(-1x+5)
We multiply parentheses
-0.2x+1
Back to the equation:
-(-0.2x+1)
We get rid of parentheses
0.9x+0.2x-1-1.2=0
We add all the numbers together, and all the variables
1.1x-2.2=0
We move all terms containing x to the left, all other terms to the right
1.1x=2.2
x=2.2/1.1
x=2

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