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0.9x-20=2/3x
We move all terms to the left:
0.9x-20-(2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
0.9x-(+2/3x)-20=0
We get rid of parentheses
0.9x-2/3x-20=0
We multiply all the terms by the denominator
(0.9x)*3x-20*3x-2=0
We add all the numbers together, and all the variables
(+0.9x)*3x-20*3x-2=0
We multiply parentheses
0x^2-20*3x-2=0
Wy multiply elements
0x^2-60x-2=0
We add all the numbers together, and all the variables
x^2-60x-2=0
a = 1; b = -60; c = -2;
Δ = b2-4ac
Δ = -602-4·1·(-2)
Δ = 3608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3608}=\sqrt{4*902}=\sqrt{4}*\sqrt{902}=2\sqrt{902}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{902}}{2*1}=\frac{60-2\sqrt{902}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{902}}{2*1}=\frac{60+2\sqrt{902}}{2} $
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