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0/06x+0/3x=7/2
We move all terms to the left:
0/06x+0/3x-(7/2)=0
Domain of the equation: 06x!=0
x!=0/06
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
0/06x+0/3x-(+7/2)=0
We get rid of parentheses
0/06x+0/3x-7/2=0
We calculate fractions
(-378x^2)/72x^2+()/72x^2+()/72x^2=0
We multiply all the terms by the denominator
(-378x^2)+()+()=0
We add all the numbers together, and all the variables
(-378x^2)=0
We get rid of parentheses
-378x^2=0
a = -378; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-378)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-756}=0$
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