0/12x+5+3x=10+2x

Solution for 0/12x+5+3x=10+2x equation:

0/12x+5+3x=10+2x

We move all terms to the left:

0/12x+5+3x-(10+2x)=0


Domain of the equation: 12x!=0

x!=0/12

x!=0

x∈R


We add all the numbers together, and all the variables

0/12x+3x-(2x+10)+5=0

We add all the numbers together, and all the variables

3x+0/12x-(2x+10)+5=0

We get rid of parentheses

3x+0/12x-2x-10+5=0

We multiply all the terms by the denominator


3x*12x-2x*12x-10*12x+5*12x+0=0

We add all the numbers together, and all the variables

3x*12x-2x*12x-10*12x+5*12x=0

Wy multiply elements

36x^2-24x^2-120x+60x=0

We add all the numbers together, and all the variables

12x^2-60x=0

a = 12; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·12·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*12}=\frac{120}{24}
=5
$