012(6)+0.02x=0.04(12+x)

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Solution for 012(6)+0.02x=0.04(12+x) equation: 



012(6)+0.02x=0.04(12+x)

We move all terms to the left:

012(6)+0.02x-(0.04(12+x))=0

We add all the numbers together, and all the variables

0.02x-(0.04(x+12))+0126=0

We add all the numbers together, and all the variables

0.02x-(0.04(x+12))+126=0



We calculate terms in parentheses: -(0.04(x+12)), so:

0.04(x+12)

We multiply parentheses

0.04x+0.48

Back to the equation:

-(0.04x+0.48)



We get rid of parentheses

0.02x-0.04x-0.48+126=0

We add all the numbers together, and all the variables

-0.02x+125.52=0

We move all terms containing x to the left, all other terms to the right

-0.02x=-125.52

x=-125.52/-0.02

x=+6276

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