0121x2+44x+4=0

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Solution for 0121x2+44x+4=0 equation: 



0121x^2+44x+4=0

a = 0121; b = 44; c = +4;
Δ = b2-4ac
Δ = 442-4·0121·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-44}{242}=-2/11$

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