014-0.03(x+2)=-0.02(1-x)

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Solution for 014-0.03(x+2)=-0.02(1-x) equation: 



014-0.03(x+2)=-0.02(1-x)

We move all terms to the left:

014-0.03(x+2)-(-0.02(1-x))=0

We add all the numbers together, and all the variables

-0.03(x+2)-(-0.02(-1x+1))+014=0

We add all the numbers together, and all the variables

-0.03(x+2)-(-0.02(-1x+1))+14=0

We multiply parentheses

-0.03x-(-0.02(-1x+1))-0.06+14=0



We calculate terms in parentheses: -(-0.02(-1x+1)), so:

-0.02(-1x+1)

We multiply parentheses

0.02x-0.02

Back to the equation:

-(0.02x-0.02)



We add all the numbers together, and all the variables

-0.03x-(0.02x-0.02)+13.94=0

We get rid of parentheses

-0.03x-0.02x+0.02+13.94=0

We add all the numbers together, and all the variables

-0.05x+13.96=0

We move all terms containing x to the left, all other terms to the right

-0.05x=-13.96

x=-13.96/-0.05

x=279+0.0099999999999998/0.05

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