04(2x-7)+1,2(3x+0,7)=1,6x

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Solution for 04(2x-7)+1,2(3x+0,7)=1,6x equation:


04(2x-7)+1,2(3x,7)=1,6x

We simplify the equation to the form, which is simple to understand
04(2x-7)+1,2(3x,7)=1,6x

Reorder the terms in parentheses
+(+8x-28)+1,2*(3x,7)=1,6x

Remove unnecessary parentheses
+8x-28+1,2+*(+3x,7+)=+1,6x

Reorder the terms in parentheses
+8x-28+(+3.6x + 0.84)=1,6x

Remove unnecessary parentheses
+8x-28+3.6x + 0.84=+1,6x

We move all terms containing x to the left and all other terms to the right.
+8x+3.6x-1.6x=+28-0.84

We simplify left and right side of the equation.
+10x=+27.16

We divide both sides of the equation by 10 to get x.
x=2.716

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