0=((12+x)+(1.57x))-30

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Solution for 0=((12+x)+(1.57x))-30 equation: 



0=((12+x)+(1.57x))-30

We move all terms to the left:

0-(((12+x)+(1.57x))-30)=0

We add all the numbers together, and all the variables

-(((x+12)+(+1.57x))-30)+0=0

We add all the numbers together, and all the variables

-(((x+12)+(+1.57x))-30)=0



We calculate terms in parentheses: -(((x+12)+(+1.57x))-30), so:

((x+12)+(+1.57x))-30



We calculate terms in parentheses: +((x+12)+(+1.57x)), so:

(x+12)+(+1.57x)

We get rid of parentheses

x+1.57x+12

We add all the numbers together, and all the variables

2.57x+12

Back to the equation:

+(2.57x+12)



We get rid of parentheses

2.57x+12-30

We add all the numbers together, and all the variables

2.57x-18

Back to the equation:

-(2.57x-18)



We get rid of parentheses

-2.57x+18=0

We move all terms containing x to the left, all other terms to the right

-2.57x=-18

x=-18/-2.57

x=7+0.010000000000002/2.57

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