0=((12+x)+(1.57x))-30

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Solution for 0=((12+x)+(1.57x))-30 equation:



0=((12+x)+(1.57x))-30
We move all terms to the left:
0-(((12+x)+(1.57x))-30)=0
We add all the numbers together, and all the variables
-(((x+12)+(+1.57x))-30)+0=0
We add all the numbers together, and all the variables
-(((x+12)+(+1.57x))-30)=0
We calculate terms in parentheses: -(((x+12)+(+1.57x))-30), so:
((x+12)+(+1.57x))-30
We calculate terms in parentheses: +((x+12)+(+1.57x)), so:
(x+12)+(+1.57x)
We get rid of parentheses
x+1.57x+12
We add all the numbers together, and all the variables
2.57x+12
Back to the equation:
+(2.57x+12)
We get rid of parentheses
2.57x+12-30
We add all the numbers together, and all the variables
2.57x-18
Back to the equation:
-(2.57x-18)
We get rid of parentheses
-2.57x+18=0
We move all terms containing x to the left, all other terms to the right
-2.57x=-18
x=-18/-2.57
x=7+0.010000000000002/2.57

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