0=(-5i)(-7i)

Solution for 0=(-5i)(-7i) equation:

0=(-5i)(-7i)

We move all terms to the left:

0-((-5i)(-7i))=0

We add all the numbers together, and all the variables

-((-5i)(-7i))=0

We multiply parentheses ..

-((+35i^2))=0


We calculate terms in parentheses: -((+35i^2)), so:

(+35i^2)

We get rid of parentheses

35i^2

Back to the equation:

-(35i^2)


a = -35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-35)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{0}{-70}=0$