0=(1-x)+2(x+1)-3(1-x)

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Solution for 0=(1-x)+2(x+1)-3(1-x) equation:



0=(1-x)+2(x+1)-3(1-x)
We move all terms to the left:
0-((1-x)+2(x+1)-3(1-x))=0
We add all the numbers together, and all the variables
-((-1x+1)+2(x+1)-3(-1x+1))+0=0
We add all the numbers together, and all the variables
-((-1x+1)+2(x+1)-3(-1x+1))=0
We calculate terms in parentheses: -((-1x+1)+2(x+1)-3(-1x+1)), so:
(-1x+1)+2(x+1)-3(-1x+1)
We multiply parentheses
(-1x+1)+2x+3x+2-3
We get rid of parentheses
-1x+2x+3x+1+2-3
We add all the numbers together, and all the variables
4x
Back to the equation:
-(4x)
x=0/-4
x=0

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