0=(1-x)+2(x+1)-3(1-x)

Solution for 0=(1-x)+2(x+1)-3(1-x) equation:

0=(1-x)+2(x+1)-3(1-x)

We move all terms to the left:

0-((1-x)+2(x+1)-3(1-x))=0

We add all the numbers together, and all the variables

-((-1x+1)+2(x+1)-3(-1x+1))+0=0

We add all the numbers together, and all the variables

-((-1x+1)+2(x+1)-3(-1x+1))=0


We calculate terms in parentheses: -((-1x+1)+2(x+1)-3(-1x+1)), so:

(-1x+1)+2(x+1)-3(-1x+1)

We multiply parentheses

(-1x+1)+2x+3x+2-3

We get rid of parentheses

-1x+2x+3x+1+2-3

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)


x=0/-4

x=0