0=(2+0.2x)(500-20x)

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Solution for 0=(2+0.2x)(500-20x) equation: 



0=(2+0.2x)(500-20x)

We move all terms to the left:

0-((2+0.2x)(500-20x))=0

We add all the numbers together, and all the variables

-((0.2x+2)(-20x+500))+0=0

We add all the numbers together, and all the variables

-((0.2x+2)(-20x+500))=0

We multiply parentheses ..

-((+0x^2+0x-40x+1000))=0



We calculate terms in parentheses: -((+0x^2+0x-40x+1000)), so:

(+0x^2+0x-40x+1000)

We get rid of parentheses

0x^2+0x-40x+1000

We add all the numbers together, and all the variables

x^2-39x+1000

Back to the equation:

-(x^2-39x+1000)



We get rid of parentheses

-x^2+39x-1000=0

We add all the numbers together, and all the variables

-1x^2+39x-1000=0

a = -1; b = 39; c = -1000;
Δ = b2-4ac
Δ = 392-4·(-1)·(-1000)
Δ = -2479
Delta is less than zero, so there is no solution for the equation

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