0=(2+i)+(-3+8i)

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Solution for 0=(2+i)+(-3+8i) equation: 



0=(2+i)+(-3+8i)

We move all terms to the left:

0-((2+i)+(-3+8i))=0

We add all the numbers together, and all the variables

-((i+2)+(8i-3))+0=0

We add all the numbers together, and all the variables

-((i+2)+(8i-3))=0



We calculate terms in parentheses: -((i+2)+(8i-3)), so:

(i+2)+(8i-3)

We get rid of parentheses

i+8i+2-3

We add all the numbers together, and all the variables

9i-1

Back to the equation:

-(9i-1)



We get rid of parentheses

-9i+1=0

We move all terms containing i to the left, all other terms to the right

-9i=-1

i=-1/-9

i=1/9

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