0=(25+4.9x)x

Solution for 0=(25+4.9x)x equation:

0=(25+4.9x)x

We move all terms to the left:

0-((25+4.9x)x)=0

We add all the numbers together, and all the variables

-((4.9x+25)x)+0=0

We add all the numbers together, and all the variables

-((4.9x+25)x)=0


We calculate terms in parentheses: -((4.9x+25)x), so:

(4.9x+25)x

We multiply parentheses

4x^2+25x

Back to the equation:

-(4x^2+25x)


We get rid of parentheses

-4x^2-25x=0

a = -4; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·(-4)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*-4}=\frac{50}{-8}
=-6+1/4
$