0=(2cos(2x))-(2cos(x))

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Solution for 0=(2cos(2x))-(2cos(x)) equation:


Simplifying
0 = (2cos(2x)) + -1(2cos(x))

Remove parenthesis around (2x)
0 = (2cos * 2x) + -1(2cos(x))

Reorder the terms for easier multiplication:
0 = (2 * 2cos * x) + -1(2cos(x))

Multiply 2 * 2
0 = (4cos * x) + -1(2cos(x))

Multiply cos * x
0 = (4cosx) + -1(2cos(x))

Multiply cos * x
0 = (4cosx) + -1(2cosx)

Remove parenthesis around (2cosx)
0 = (4cosx) + -1 * 2cosx

Multiply -1 * 2
0 = (4cosx) + -2cosx

Combine like terms: (4cosx) + -2cosx = 2cosx
0 = 2cosx

Solving
0 = 2cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2cosx' to each side of the equation.
0 + -2cosx = 2cosx + -2cosx
Remove the zero:
-2cosx = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
-2cosx = 0

Divide each side by '-2'.
cosx = 0

Simplifying
cosx = 0

The solution to this equation could not be determined.

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