0=(2x)(60-2x)

Solution for 0=(2x)(60-2x) equation:

0=(2x)(60-2x)

We move all terms to the left:

0-((2x)(60-2x))=0

We add all the numbers together, and all the variables

-(2x(-2x+60))+0=0

We add all the numbers together, and all the variables

-(2x(-2x+60))=0


We calculate terms in parentheses: -(2x(-2x+60)), so:

2x(-2x+60)

We multiply parentheses

-4x^2+120x

Back to the equation:

-(-4x^2+120x)


We get rid of parentheses

4x^2-120x=0

a = 4; b = -120; c = 0;
Δ = b2-4ac
Δ = -1202-4·4·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-120}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+120}{2*4}=\frac{240}{8}
=30
$