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0=(3-2i)-(-2+3i)
We move all terms to the left:
0-((3-2i)-(-2+3i))=0
We add all the numbers together, and all the variables
-((-2i+3)-(3i-2))+0=0
We add all the numbers together, and all the variables
-((-2i+3)-(3i-2))=0
We calculate terms in parentheses: -((-2i+3)-(3i-2)), so:We get rid of parentheses
(-2i+3)-(3i-2)
We get rid of parentheses
-2i-3i+3+2
We add all the numbers together, and all the variables
-5i+5
Back to the equation:
-(-5i+5)
5i-5=0
We move all terms containing i to the left, all other terms to the right
5i=5
i=5/5
i=1
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