0=(3-2i)-(-2+3i)

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Solution for 0=(3-2i)-(-2+3i) equation: 



0=(3-2i)-(-2+3i)

We move all terms to the left:

0-((3-2i)-(-2+3i))=0

We add all the numbers together, and all the variables

-((-2i+3)-(3i-2))+0=0

We add all the numbers together, and all the variables

-((-2i+3)-(3i-2))=0



We calculate terms in parentheses: -((-2i+3)-(3i-2)), so:

(-2i+3)-(3i-2)

We get rid of parentheses

-2i-3i+3+2

We add all the numbers together, and all the variables

-5i+5

Back to the equation:

-(-5i+5)



We get rid of parentheses

5i-5=0

We move all terms containing i to the left, all other terms to the right

5i=5

i=5/5

i=1

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