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0=(3n-3)(3n+3)
We move all terms to the left:
0-((3n-3)(3n+3))=0
We add all the numbers together, and all the variables
-((3n-3)(3n+3))=0
We use the square of the difference formula
9n^2+9=0
a = 9; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·9·9
Δ = -324
Delta is less than zero, so there is no solution for the equation
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