0=(3x+15)/(4x-12)

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Solution for 0=(3x+15)/(4x-12) equation: 



0=(3x+15)/(4x-12)

We move all terms to the left:

0-((3x+15)/(4x-12))=0



Domain of the equation: (4x-12))!=0

x∈R



We add all the numbers together, and all the variables

-((3x+15)/(4x-12))=0

We multiply all the terms by the denominator


-((3x+15)=0



We calculate terms in parentheses: -((3x+15), so:

(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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(3x+15





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