0=(5y-2)(5y+2)

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Solution for 0=(5y-2)(5y+2) equation:


Simplifying
0 = (5y + -2)(5y + 2)

Reorder the terms:
0 = (-2 + 5y)(5y + 2)

Reorder the terms:
0 = (-2 + 5y)(2 + 5y)

Multiply (-2 + 5y) * (2 + 5y)
0 = (-2(2 + 5y) + 5y * (2 + 5y))
0 = ((2 * -2 + 5y * -2) + 5y * (2 + 5y))
0 = ((-4 + -10y) + 5y * (2 + 5y))
0 = (-4 + -10y + (2 * 5y + 5y * 5y))
0 = (-4 + -10y + (10y + 25y2))

Combine like terms: -10y + 10y = 0
0 = (-4 + 0 + 25y2)
0 = (-4 + 25y2)

Solving
0 = -4 + 25y2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-25y2' to each side of the equation.
0 + -25y2 = -4 + 25y2 + -25y2
Remove the zero:
-25y2 = -4 + 25y2 + -25y2

Combine like terms: 25y2 + -25y2 = 0
-25y2 = -4 + 0
-25y2 = -4

Divide each side by '-25'.
y2 = 0.16

Simplifying
y2 = 0.16

Take the square root of each side:
y = {-0.4, 0.4}

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