0=(8x+9)(8x+3)

Solution for 0=(8x+9)(8x+3) equation:

0=(8x+9)(8x+3)

We move all terms to the left:

0-((8x+9)(8x+3))=0

We add all the numbers together, and all the variables

-((8x+9)(8x+3))=0

We multiply parentheses ..

-((+64x^2+24x+72x+27))=0


We calculate terms in parentheses: -((+64x^2+24x+72x+27)), so:

(+64x^2+24x+72x+27)

We get rid of parentheses

64x^2+24x+72x+27

We add all the numbers together, and all the variables

64x^2+96x+27

Back to the equation:

-(64x^2+96x+27)


We get rid of parentheses

-64x^2-96x-27=0

a = -64; b = -96; c = -27;
Δ = b2-4ac
Δ = -962-4·(-64)·(-27)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-48}{2*-64}=\frac{48}{-128}
=-3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+48}{2*-64}=\frac{144}{-128}
=-1+1/8
$