0=(m+4)(m-4)

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Solution for 0=(m+4)(m-4) equation: 



0=(m+4)(m-4)

We move all terms to the left:

0-((m+4)(m-4))=0

We add all the numbers together, and all the variables

-((m+4)(m-4))=0

We use the square of the difference formula

m^2+16=0

a = 1; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·1·16
Δ = -64
Delta is less than zero, so there is no solution for the equation

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