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0=(x)(x)+16x-22
We move all terms to the left:
0-((x)(x)+16x-22)=0
We add all the numbers together, and all the variables
-(16x+xx-22)+0=0
We add all the numbers together, and all the variables
-(16x+xx-22)=0
We get rid of parentheses
-16x-xx+22=0
We move all terms containing x to the left, all other terms to the right
-16x-xx=-22
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