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0=(x+10)(x-6)
We move all terms to the left:
0-((x+10)(x-6))=0
We add all the numbers together, and all the variables
-((x+10)(x-6))=0
We multiply parentheses ..
-((+x^2-6x+10x-60))=0
We calculate terms in parentheses: -((+x^2-6x+10x-60)), so:We get rid of parentheses
(+x^2-6x+10x-60)
We get rid of parentheses
x^2-6x+10x-60
We add all the numbers together, and all the variables
x^2+4x-60
Back to the equation:
-(x^2+4x-60)
-x^2-4x+60=0
We add all the numbers together, and all the variables
-1x^2-4x+60=0
a = -1; b = -4; c = +60;
Δ = b2-4ac
Δ = -42-4·(-1)·60
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*-1}=\frac{-12}{-2} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*-1}=\frac{20}{-2} =-10 $
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